Y=2x^2-32x+56

Solution for Y=2x^2-32x+56 equation:

=2Y^2-32Y+56

We move all terms to the left:

-(2Y^2-32Y+56)=0

We get rid of parentheses

-2Y^2+32Y-56=0

a = -2; b = 32; c = -56;
Δ = b2-4ac
Δ = 322-4·(-2)·(-56)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-24}{2*-2}=\frac{-56}{-4}
=+14
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+24}{2*-2}=\frac{-8}{-4}
=+2
$